Comparison with Elastic Deuteron Asymmetry (continue from last week)

I am working on the comparison of the Elastic Deuteron asymmetry to our measured data at pmiss = 0. Last week I mentioned email from Zilu Zhu. He suggested that Pzz = 1, if the spin of the deuteron exactly follows the spin of the 3He. Please see the following link:

DeuteronElasticAsymmetryNotes.pdf

I was thinking a bit more about this thing, and realized, that this is not true. In the S-state, 3He wave function can be written as:

|He> = sqrt(2/3)|d,1,1>|p,1/2,-1/2> - sqrt(1/3)|d,1,0>|p,1/2,1/2>,

which means, that 3He wave-function also contains deuteron state, without vector polarization. This means, that Pzz can be different from 1.

Using formulas from Zilu's thesis (see the following link: ZiLu1PageChap3.pdf) I determined, that Pz = 2/3 and Pzz=0. Considering this in my calculation for Deuteron Elastic Asymmetry, I realized, that this slightly increases the absolute value of the longitudinal asymmetry (AL~-3%), while decreases the transverse asymmetry (AT~-2%).

01.)

02.)

I will continue working on this topic (discuss this result with Simon).

Last modified: 10/03/12